The Weight of Iron in Water: Explained with Buoyancy
In this article, we will explore the concept of buoyancy and demonstrate how to calculate the weight of an iron piece when it is immersed in water. We will use a real-world example to illustrate the process.
Understanding Density and Buoyancy
Buoyancy is a fundamental principle in physics, and it plays a crucial role in understanding the behavior of objects when submerged in fluids. The concept of density is essential in this discussion, as it is the ratio of the mass of an object to its volume.
Calculating the Volume of the Iron Piece
Given that the weight of the iron piece is 400 g and the relative density of iron is 7.8, we can calculate its volume using the formula:
```text{Density of iron} 7.8 times 1000 kg/m^3 7800 kg/m^3```Using the formula Density Mass/Volume, we can rearrange it to Volume Mass/Density. Substituting the given values:
```Volume of iron 0.4 kg / 7800 kg/m^3 5.128 times 10^{-5} m^3```Calculating the Weight of the Displaced Water
The weight of the water displaced is equal to the volume of the iron piece multiplied by the density of water. Given that the density of water is approximately 1000 kg/m3, we can calculate the weight of the displaced water as follows:
```Weight of water displaced Volume times Density of water Weight of water displaced 5.128 times 10^{-5} m^3 times 1000 kg/m^3 0.05128 kg 51.28 g```Calculating the Apparent Weight of the Iron Piece in Water
The apparent weight of the iron piece in water is the actual weight of the iron piece minus the weight of the displaced water. Using the given values, we can calculate it as follows:
```Apparent weight Weight in air - Weight of water displaced Apparent weight 400 g - 51.28 g approx 348.72 g```Explanation of Steps
Given Data: Weight of iron piece 400 g Relative density of iron 7.8 Density of water 1000 kg/m3 Calculate the volume of the iron piece: Using Volume Mass/Density, Volume of iron 0.4 kg / 7800 kg/m3. Calculate the weight of the displaced water: Using Weight of water displaced Volume times Density of water, Weight of water displaced 5.128 times 10-5 m3 times 1000 kg/m3 0.05128 kg 51.28 g. Calculate the apparent weight of the iron piece in water: Applying the formula Apparent weight Weight in air - Weight of water displaced, Apparent weight 400 g - 51.28 g approx 348.72 g.Conclusion
The weight of the iron piece when immersed in water is approximately 348.72 grams. This calculation demonstrates the principle of buoyancy and its application in determining the weight of objects in fluids.
Related Keywords:
Buoyancy Density Iron Weight in WaterTags: physics, fluid dynamics, Archimedes' principle, object displacement, buoyant force.