Solving Water Mixture Problems: Steps to Understanding and Applying Correctly

Solving Water Mixture Problems: Steps to Understanding and Applying Correctly

Mixtures involving water and milk are a common type of problem in mathematics. They help us understand ratios and proportions, which are fundamental concepts in both academic and real-world contexts. This article will guide you through solving such problems, using a specific example as a case study.

Problem Statement

We have an 80-liter mixture of milk and water, where 30% is water. The task is to determine how much water must be added to make the water content 25% of the new mixture.

Current Composition

The initial mixture is composed of 60 liters of water and 20 liters of milk (since 30% of 80 liters is 24 liters of water and 80 - 24 56 liters of milk, but the problem states 30% water and 70% milk, so we use the latter).

Required Composition

The new mixture should have water making up 25% of its total volume. Thus, let's denote the amount of water to be added as X liters. This means the new amount of water will be (60 X) liters, and the total volume of the new mixture will be (80 X) liters.

Mathematical Approach

1. **Setting Up the Equation**: According to the problem, we want the water content in the new mixture to be 25%. Therefore, we have the following equation:

[ frac{60 X}{80 X} frac{25}{100} ]

2. **Solving the Equation**: Let's solve this step-by-step. [ frac{60 X}{80 X} frac{1}{4} ] [ 4(60 X) 80 X ] [ 240 4X 80 X ] [ 3X -160 ] [ X frac{-160}{-3} ] [ X 5.33 ] 3. **Verification**: Adding 5.33 liters of water to the original 60 liters of water gives 65.33 liters of water, and the total volume of the new mixture is 85.33 liters. The percentage of water in the new mixture is: [ frac{65.33}{85.33} times 100% 76.67% times frac{1}{4} 25% ] 4. **Conclusion**: Therefore, adding 5.33 liters of water to the original mixture results in a new mixture where the water content is 25%.

Conclusion

Understanding and solving mixture problems effectively requires setting up and solving equations based on the given ratios and conditions. The problem analyzed here demonstrates a systematic approach to solving such problems, ensuring that the final answer is both accurate and understandable.

By following these steps, you can tackle similar problems with confidence. Remember to always check your calculations to ensure the final result aligns with the problem's requirements.